If f(1)=0 and dfdx>f(x)∀x≥1 , then
fx>0
fx>1
fx>e
fx>1e
dfdx−f(x)>0⇒e−xdfdx−f(x)>e⇒ddxe−x⋅f(x)>0⇒e−x⋅f(x) is on increasing function f(1)=0→e−x⋅f(x)>0→f(x)>0