If f is an even function defined on the interval [– 5, 5], then the real values of x satisfying the equation f(x)=fx+1x+2 are

Since f(x)=fx+1x+2⇒x=x+1x+2 ⇒    x2+x−1=0⇒    x=−1±52   ......(1)Since f (x) is an even function defined on [–5, 5],∴f(−x)=f(x),∀x∈[−5,5]⇒x=−x+1x+2⇒x2+3x+1=0⇒x=−3±52   ......(2)From Eq. (1) and (2), the values of x are−1±52 and −3±52