First slide

Introduction to limits

Question

If $f (a) = 2, f^{1} (a) = 1, g (a) = - 1, g^{1} (a) = 2$ then $\underset{x \to a}{L i m} \frac{g (x) f (a) - g (a) f (x)}{x - a} =$

Moderate

A

$\frac{1}{5}$
B

5
C

$- \frac{1}{5}$
D

-5

Solution

$f (a) = 2, f^{'} (a) = 1, g (a) = - 1, g^{'} (a) = 2$ $\underset{x \to a}{^{\lim}} \frac{g (x) f (a) - g (a) f (x)}{x - a}$ By L - H Rule = $\lim_{x \to a} \frac{g^{1} (x) f (a) - f^{1} (x) g (a)}{1 - 0} = g^{1} (a) f (a) - f^{1} (a) g (a)$ =(2) (2) -(-1)(1) =5

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App