If f is a function such that f(0)=2, f(1)=3 and f(x+2)=2f(x)−f(x+1) for every real x, then f(5) is

x=0⇒f(2)=2f(0)−f(1)=2×2−3=1x=1⇒f(3)=6−1=5x=2⇒f(4)=2f(2)−f(3)=2×1−5=−3x=3⇒f(5)=2f(3)−f(4)=2(5)−(−3)=13