First slide

Algebra of real valued functions

Question

If f = {(-2, 4), (0, 6), (2, 8)} and
g = {(-2, -1), (0, 3), (2, 5)}, then $(\frac{2 f}{3 g} + \frac{3 g}{2 f}) (0)$ =_______

Moderate

A

2.08
B

2.14
C

2.32
D

2.60

Solution

$(\frac{2 f}{3 g} + \frac{3 g}{2 f}) (0) = \frac{2 f (0)}{3 g (0)} + \frac{3 g (0)}{2 f (0)} = \frac{25}{12}$

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