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$If f : [1, \infty) \to [2, \infty) is given by f (x) = x + \frac{1}{x}, then f^{- 1} (x) equals$

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x+x2−42

x1+x2

x−x2−42

1+x2−4

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Correct option is A

f:[1,∞)→[2,∞) f(x)=x+1x=y or x2−yx+1=0 or x=y±y2−42 But given f:[1,∞)→[2,∞)∴ x=y+y2−42 or f−1(x)=x+x2−42

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If f:[1,∞)→[2,∞) is given by f(x)=x+1x, then f−1(x) equals

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

$If f : [1, \infty) \to [2, \infty) is given by f (x) = x + \frac{1}{x}, then f^{- 1} (x) equals$