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Q.

If f:[1,∞)→[2,∞) is given by f(x)=x+1x, then f−1(x) equals

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a

x+x2−42

b

x1+x2

c

x−x2−42

d

1+x2−4

answer is A.

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Detailed Solution

f:[1,∞)→[2,∞) f(x)=x+1x=y or x2−yx+1=0 or x=y±y2−42 But given f:[1,∞)→[2,∞)∴ x=y+y2−42 or f−1(x)=x+x2−42

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