If λ,β≠0,and fn=λn+βn and 31+f11+f21+f11+f21+f31+f21+f31+f4=K1−α21−β2α−β2 Then K=

We have31+f(1)1+f(2)1+f(1)1+f(2)1+f(3)1+f(2)1+f(3)1+f(4) ⇒31+α+β1+α2+β21+α+β1+α2+β21+α3+β31+α2+β21+α3+β31+α4+β4=11121αβ1α2β211121αα21ββ2                                                                    =11121αβ1α2β211121αβ1α2β2                                                                    =1-α2α-β2β-12                                                                    =k1-α21-β2α-β2 ⇒k=1