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Questions  

If f is an odd function, then the value of aaf(sinx)f(cosx)+fsin2xdx is equal to 

a
0
b
f(cos⁡x)+f(sin⁡x)
c
1
d
None of these

detailed solution

Correct option is A

f(sin⁡x)f(cos⁡x)+fsin2⁡x is odd function  since f(sin⁡-x)f(cos⁡-x)+fsin2⁡-x=-f(sin⁡x)f(cos⁡x)+fsin2⁡x since fx is odd∫−aa f(sin⁡x)f(cos⁡x)+fsin2⁡xdx=0

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