If f:R→R defined by f(x)=x4+2 then the value of f-1(83) and f-1(-2) respectively are
∅,{3,–3}
{3,–3},∅
{4,–4},∅
{4,–4},{2,-2}
f(x)=x4+2 =y⇒ x=y–21/4⇒ f-1(x)=(x-2)1/4⇒ f-1(83)=(81)1/4=±3and f-1(-2)=(-4)1/4=∅.