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If $f : R \to R$ defined by $f (x) = x^{4} + 2$ then the value of $f^{- 1} (83)$ and $f^{- 1} (- 2)$ respectively are

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∅,{3,–3}

{3,–3},∅

{4,–4},∅

{4,–4},{2,-2}

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detailed solution

Correct option is B

f(x)=x4+2 =y⇒ x=y–21/4⇒ f-1(x)=(x-2)1/4⇒ f-1(83)=(81)1/4=±3and f-1(-2)=(-4)1/4=∅.

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If f:R→R defined by f(x)=x4+2 then the value of f-1(83) and f-1(-2) respectively are

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If $f : R \to R$ defined by $f (x) = x^{4} + 2$ then the value of $f^{- 1} (83)$ and $f^{- 1} (- 2)$ respectively are