If f : R→ R, defined by f (x) = x3 + 7, then the value of f –1(71) and f –1 (–1) respectively are
4, ∅
∅ , -2
4,-2
2,-4
f (x) = x3+ 7 = 71 ⇒ x3 = 64 ⇒ x = 4
⇒ f-1(71)=4
and f(x)=x3+7=–1⇒x3=–8⇒x=–2⇒f-1(–1)=–2