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Q.

If f:R→R  defined by f(x)=x2−1 then the set of all pre-images of 15=f−1(15)  the set of all pre-images of −3=f−1(−3) are respectively

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a

φ,  {4,  −4}

b

{3,  −3},  ϕ

c

{4 , −4}  , φ

d

{4 , −4}, {2 , −2}

answer is C.

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Detailed Solution

f(x)=x2-1⇒f-1(x)=±x+1 f-1(15)=±4 f-1(-3)=∅
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