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If f : R → R is a function satisfying the property f (2x + 3) + f (2x + 7) = 2, ∀ x ∈ R, then the period of f (x) is

a
2
b
4
c
8
d
12

detailed solution

Correct option is B

We have,f (2x + 3) + f (2x + 7) = 2                (1)Replace x by x + 1,f (2x + 5) + f (2x + 9) = 2                (2)Now replace x by,x + 2, f (2x + 7) + f (2x + 11) = 2     (3)From (1) – (3), we getf (2x + 3) – f (2x + 11) = 0i.e., f (2x + 3) = f (2x + 11) ⇒ T = 4

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