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If are continuous functions then the value of the integral
is
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a
1
b
0
c
-1
d
π
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Correct option is B
Let F(x) =(f(x)+f(-x))(g(x)-g(-x)) so F(−x)=(f(−x)+f(x))(g(−x)−g(x))=−F(x).Hence ∫−π/2π/2 f(x)dx=0. (since F(x) is odd function)Similar Questions
The value of is
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