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Questions  

If f:RS is given by fx=sinx3cosx+1 is onto, then interval of S is

a
0,1
b
−1,1
c
0,3
d
−1,3

detailed solution

Correct option is D

We have  −a2+b2≤asinx+bcosx≤a2+b2So −1+3≤sinx−3cosx≤1+3⇒−2≤sinx−3cosx≤2⇒−2+1≤sinx−3cosx+1≤2+1⇒−1≤fx≤3⇒S=-1,3

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