If a∈(0,1), and f(a)=a2−a+1+8sin2aa2−a+1+27cosec2aa2−a+1, then the least value of f(a) is
Using A.M. ≥ G.M. (for positive numbers)
a2−a+1+8sin2aa2−a+1+27cosec2aa2−a+1
≥3a2−a+18sin2aa2−a+127cosec2aa2−a+113=3233313=3(6)=18