If f(2tanx1+tan2x)=
(cos2x+1)(sec2x+2tanx)2 then f(1)=
2
1
3
4
f(2tanx1+tan2x)=2cos2x(1+tanx)22
=1+tan2x+2tanx1+tan2x=1+2tanx1+tan2x
∴f(4)=5