If f(x)  be continuous function for all real values of x  and satisfies; x2+f(x)−2x+23−3−3 f(x)=0, ∀    x∈R.  Then the value of f(3)  is

A sf(x) is continuous for all x∈R Thus, limx→3f(x)=f(3)Where f(x)=x2−2x+23−33−x,  x≠3limx→3f(x)=limx→3x2−2x+23−33−x=limx→3(2−3−x)(3−x)(3−x)=2(1−3)⇒f(3)=2(1−3)