If f(x)=a+bx+cx2 and α, β, γ are the roots of the equation x3=1, then a b cb c ac a b is equal to
f(α)+f(β)+f(γ)
f(α)f(β)+f(β)f(γ)+f(γ)f(α)
f(α)f(β)f(γ)
−f(α)f(β)f(γ)
abcbcacab=−a3+b3+c3−3abc=−(a+b+c)a+bω2+cωa+bω+cω2
(where ω is cube roots of unity)
=−f(α)f(β)f(γ) ∵α=1,β=ω,γ=ω2