If f(x) is a continuous function ∀x∈R and f(x)∈(1,30) and g(x)=f(x)a where [.] denotes the greatest integer function is continuous then the least positive integral value of a is
g(x)=f(x)a is continuous if f(x)a=0 for ∀f(x)
f(x)∈(1,30) for which we must have a>30
Hence the least value of a is 6.