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If f(x)=cosxcos2x+cos3x then f(x)d¨x is equal to

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a
tan⁡x2+C
b
x-tan⁡x2+C
c
x−12tan⁡x2+C
d
x−tan⁡x22+C

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detailed solution

Correct option is B

∵f(x)=cos⁡x−cos2⁡x+cos3⁡x−…∞=cos⁡x1+cos⁡x∴∫f(x)dx=∫1+cos⁡x1+cos⁡xdx−∫11+cos⁡xdx =x−12∫sec2⁡x2dx =x−12tan⁡x2⋅2+C=x−tan⁡x2+C


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