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Questions  

If f(x)=cosx and g(x)=sinx then logf(x)(f(x))2dx is 

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a
f(x)(log⁡f(x)+1)+x+C
b
g(x)f(x)(log⁡f(x)+1)+x22+C
c
f(x)g(x)(log⁡g(x)+1)+x+C
d
g(x)f(x)[log⁡f(x)+1]−x+C

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detailed solution

Correct option is D

I=∫log⁡cos⁡xcos2⁡xdx=∫sec2⁡xlog⁡cos⁡xdx=(tan⁡x)log⁡cos⁡x−∫tan⁡x−sin⁡xcos⁡xdx=(tan⁡x)log⁡cos⁡x+∫sec2−1dx=(tan⁡x)[log⁡cos⁡x+1]−x+C=g(x)f(x)[log⁡f(x)+1]−x+C


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