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If f(x)=1cos2x1+tanx then its anti-derivative F(x) ,F(0) = 4 is

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a
1+tan⁡x+4
b
23(1+tan⁡x)3/2
c
2(1+tan⁡x+1)
d
none of these

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detailed solution

Correct option is C

F(x)=∫dxcos2⁡x1+tan⁡x+C=∫11+tdt+C(t=tan⁡x)=2(1+t)+C=21+tan⁡x+CSince 4=F(0)=2+C⇒C=2 HenceF(x)=2(1+tan⁡x+1)


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