If f(x)=cosec(x+π/3)cosec(x+π/6) then the value of ∫0π/2 f(x)dx is
2 log 3
– 2 log 3
log 3
1/4
I=∫0π/2 cosec(x+π/3)cosec(x+π/6)dx=1sin(π/6)∫0π/2 sin[(x+π/3)−(x+π/6)sin(x+π/3)sin(x+π/6)dx
=2∫0π/2 [cot(x+π/6)−cot(x+π/3)]dx=2logsin(x+π/6)sin(x+π/3)0π/2=2log3/21/2−log1/23/3=2log3