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If f(x)=cosec(x+π/3)cosec(x+π/6) then the value of 0π/2f(x)dx is

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a
2 log 3
b
– 2 log 3
c
log 3
d
1/4

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detailed solution

Correct option is A

I=∫0π/2 cosec⁡(x+π/3)cosec⁡(x+π/6)dx=1sin⁡(π/6)∫0π/2 sin⁡[(x+π/3)−(x+π/6)sin⁡(x+π/3)sin⁡(x+π/6)dx=2∫0π/2 [cot⁡(x+π/6)−cot⁡(x+π/3)]dx=2log⁡sin⁡(x+π/6)sin⁡(x+π/3)0π/2=2log⁡3/21/2−log⁡1/23/3=2log⁡3


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