If f(x)=cot−1xx−x−x2 then f′(1)=
−log2
log2
1
-1
f′(x)=−11+xx−x−x22ddxxx−x−x2=4xx+x−x2xx(1+logx)+x−x(1+logx)2f′(1)=−4(1+1)21(1+log1)+1(1+log1)2=−1⋅1+12=−1.