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Questions  

If f(x)dx=ϕ(x) i.e. ϕ  is a function such that

 ϕ(x)=f(x), then x9fx5dx is equal to

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a
15x5ϕx5−∫x4ϕx5dx+C
b
15x5ϕx5−5∫x5ϕx5dx+C
c
15x5ϕx5−∫x4ϕx5dx+C
d
15x5ϕx5−∫x5ϕx5dx+C

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detailed solution

Correct option is C

Let x5=t, so ∫x9fx5dx=15∫tf(t)dt=15t∫f(t)dt−∫ϕ(t)dt=15x5ϕx5−5∫ϕx5x4dx+C=15x5ϕx5−∫x4ϕx5dx+C


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