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If f(x)dx=f(x)+C, then {f(x)}2dx is

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a
{f(x)}2+C
b
13{f(x)}3+C
c
f(x)+C
d
12{f(x)}2+C

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detailed solution

Correct option is D

Given,∫f(x)dx=f(x)+Cf(x)=f′(x)∴∫f(x)2dx=∫f(x)⋅f′(x)dx=12{f(x)}2+C


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