If 3f(x)+5f1x=1x−3,∀x(≠0)∈R , then f (x) =

We have,3f(x)+5f1x=1x−3,∀x(≠0)∈R  .......(1) ⇒3f1x+5f(x)=x−3          .......(2) Replacing x by 1xMultiplying Eq. (1) by 3 and (2) by 5 and subtracting, we get9f(x)−25f(x)=3x−9−(5x−15)⇒−14f(x)=3x−5x+6⇒f(x)=114−3x+5x−6,∀x(≠0)∈R