If 8f(x)+6f1x=x+5 and y=x2f(x) , then dydx at x=−1 is equal to
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given 8f(x)+6f1x=x+5→(1) Put x=1x⇒8f1x+6f(x)=1x+5→(2) From (1) \& (2) f(x)=1288x−6x+10y=x2f(x)⇒y=1288x3−6x+10x2