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$If 8 f (x) + 6 f (\frac{1}{x}) = x + 5 and y = x^{2} f (x), then \frac{d y}{d x} at x = - 1 is equal to$

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112

114

1914

−114

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detailed solution

Correct option is D

given 8f(x)+6f1x=x+5.........(1) ×8 Put x=1x⇒8f1x+6f(x)=1x+5.......(2) ×6solving 1 and 2 From (1)&(2) f(x)=1288x−6x+10y=x2f(x)⇒y=1288x3−6x+10x2dydx=12824x2-6+20xdydxx=−1=−114

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If 8f(x)+6f1x=x+5 and y=x2f(x) , then dydx at x=−1 is equal to

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Ready to Test Your Skills?

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$If 8 f (x) + 6 f (\frac{1}{x}) = x + 5 and y = x^{2} f (x), then \frac{d y}{d x} at x = - 1 is equal to$