If f(x) and g(x) are two functions with g(x)=x−1x and fog(x)=x3−1x3, then f(x)=
x3+3x
x2−1x2
1+1x2
3x2+3x4
fog(x)=x3−1x3,fgx=x3−1x3=x−1x3+3x−1x
fx−1x=x−1x3+3x−1xlet x−1x=t, f(t)=t3+3tThus f(x)=x3+3x