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If , then g(x) is increasing in
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a
0,π4
b
π6,π3
c
0,π3
d
π4,π2
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Correct option is D
g′(x)=f′(tanx−1)2+32(tanx−1)sec2xSince f′′(x)>0,f′(x) is increasing. So,∴ f′(tan x−1)2+3>f′(3)=0∀x∈0,π4∪π4,π2Also, (tan x−1)>0x∈π4,π2So, g(x) is increasing in π4,π2.
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If the function is strictly increasing for all values of x, then
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