If f(x)=limn→∞ xn−x−nxn+x−n,x>1 then
∫xf(x)logx+1+x21+x2dx is
logx+1+x2−x+C
12x2logx+1+x2−1+C
(x−1)logx+1+x2+C
none of these
f′(x)=limn→∞ xn−x−nxn+x−n=limn→∞ 1−(1/x)2n1+(1/x)2n=1
(1/x<1)
Using integration by parts , we get
I=∫xlogx+1+x21+x2dx=1+x2logx+1+x2dx−∫dx=1+x2logx+1+x2−x+C.