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If f(x)=limn2x+4x3++2nx2n1(0<x<1), then f(x)dx is equal to 

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a
−1−x2
b
11−x2
c
1x2−1
d
11−x2

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detailed solution

Correct option is D

Let, gn(x)=1+x2+x4+…+x2n=x2n+2−1x2−1hn(x)=gn′(x)=2xnx2n+2−(n+1)x2n+1x2−12Now f(x)=limn→∞ hn(x)=2xx2−12As 0


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