First slide
Maxima and minima
Question

 If f(x)=aloge|x|+bx2+x has extremums at x=1 and x=3 , then 

NA
Solution

 at x=1,3 we have |x|=xf(x)=alogex+bx2+xf(x)=ax+2bx+1

 According to question, f(1)=0,f(3)=0a+2b+1=0,a3+6b+1=0

 On solving, we get a=34,b=18

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