If f(x)=log(1+x2tanx)sinx3,x≠0 , has to be continuous at x=0 , then f(0)  must be defined as

For f(x)  to be continuous at x=0 f(0)=limx→0f(x) =limx→0loge(1+x2tanx)sinx3 =limx→0loge(1+x2tanx)x2tanxx2tanxsinx3 =limx→0loge(1+x2tanx)x2tanxtanxxsinx3x3=1×11=1                                                 [∵limt→0log(1+t)t=1,limx→0tanxx=limt→0sintt=1]