If $$f(x)=5log5$$⁡x then f−$$1($$α−β$$)$$ where α,β∈R is equal to

Correct option is 2f−1(α)f−1(β)

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$If f (x) = 5 \log_{5} x then f^{- 1} (α - β) where α, β \in R is equal to$

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detailed solution

Correct option is B

let fx = 5 logx 5 =y ⇒log x 5 =y5⇒x =5y5 therefore f-1x=5x5 ⇒f-1α-β=5α-β5=5α55β5=f-1αf-1β

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If f(x)=5log5⁡x then f−1(α−β) where α,β∈R is equal to

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$If f (x) = 5 \log_{5} x then f^{- 1} (α - β) where α, β \in R is equal to$