If f(x)=5log5x then f−1(α−β) where α,β∈R is equal to
f−1(α)−f−1(β)
f−1(α)f−1(β)
1f(α−β)
1f(α)−f(β)
let fx = 5 logx 5 =y ⇒log x 5 =y5⇒x =5y5
therefore f-1x=5x5 ⇒f-1α-β=5α-β5=5α55β5=f-1αf-1β