If f(x)=log1+x1−x,then
fx1⋅fx2=fx1+x2
f(x+2)−2f(x+1)+f(x)=0
f(x)+f(x+1)=fx2+x
fx1+fx2=fx1+x21+x1x2
fx1+fx2=log1+x11−x1⋅1+x21−x2=log1+x1x2+x1+x21+x1x2−x1−x2=log1+x1+x21+x1x21−x1+x21+x1x2=fx1+x21+x1x2