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 If f(x)=min|x|,1|x|,14xR then find the value of 11f(x)dx . 

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By Expert Faculty of Sri Chaitanya
a
32
b
34
c
3
d
38

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detailed solution

Correct option is D

f(x)=min|x|,1−|x|,14Now, from figure, we have∫−11 f(x)dx=2( Area of trapezium OABC)=2×12×(AB+OC)×AM=2121+1214=38


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