If f(x)=min|x|,1−|x|,14∀x∈R then find the value of ∫−11 f(x)dx .
32
34
3
38
f(x)=min|x|,1−|x|,14
Now, from figure, we have∫−11 f(x)dx=2( Area of trapezium OABC)
=2×12×(AB+OC)×AM=2121+1214=38