If f(x) is odd function and f(1)=a , and f(x+2)=f(x)+f(2) then the value of f(3) is
6a
0
9a
3a
Put x=−1⇒ f(1)=f(−1)+f(2)⇒ f(1)=−f(1)+f(2)⇒ f(2)=2a Now put x=1⇒ f(3)=f(1)+f(2)=a+2a=3a