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Q.

If f(x) is odd function and f(1)=a , and f(x+2)=f(x)+f(2) then the value of f(3) is

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a

6a

b

0

c

9a

d

3a

answer is D.

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Detailed Solution

Put x=−1⇒ f(1)=f(−1)+f(2)⇒ f(1)=−f(1)+f(2)⇒ f(2)=2a Now put x=1⇒ f(3)=f(1)+f(2)=a+2a=3a

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