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Questions  

 If f(x) is odd function and f(1)=a , and f(x+2)=f(x)+f(2) then the value of f(3) is 

a
6a
b
0
c
9a
d
3a

detailed solution

Correct option is D

Put x=−1⇒ f(1)=f(−1)+f(2)⇒ f(1)=−f(1)+f(2)⇒ f(2)=2a Now put x=1⇒ f(3)=f(1)+f(2)=a+2a=3a

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