If f(x) is a polynomical function such that f(x)⋅f(1/x)=f(x)+f(1/x) and f(2)=9 then the value of f(4)=
70
62
65
75
f(x)=xn+1⇒f(2)=2n+1⇒9=2n+1⇒23=2n⇒n=3 Clearly, f(x)=x3+1f(4)=(4)3+1=65