If f(x) is a real-valued function defined as f(x)=ln⁡(1−sin⁡x), then the graph of f(x) is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

symmetric about the line x=π

symmetric about the y-axis

symmetric about the line x=π2

symmetric about the origin

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

fπ2−x=ln⁡(1−cos⁡x) and fπ2+x=ln⁡(1−cos⁡x) Thus, fπ2+x=fπ2−x Thus, f(x) is symmetrical about line x=π2.

Watch 3-min video & get full concept clarity