If f(x)=a|sinx|+be|x|+c|x|3 andif f(x) is differentiableat x=0,then
a=b=c=0
a=b=0,c∈R
b=c=0,a∈R
a=c=0,b∈R.
For x≠0,f(x)=x2+x21+x21−11+x2=x2+1Also, f(0)=0.∴f(x) is discontinuous at x=0.