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Q.

If f(x)=sin2⁡x and the composite functions g(f(x))=|sin⁡x| then g(x) is equal to

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a

x-1

b

x

c

x+1

d

-x

answer is B.

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Detailed Solution

We have,f(x)=sin2⁡x and g(f(x))=|sin⁡x|Now, g(f(x))=|sin⁡x|⇒g(f(x))=sin2⁡x⇒g(sin2⁡x)=sin2⁡x∴g(x)=x
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