If f(x)=sin2x and the composite functions g(f(x))=|sinx| then g(x) is equal to
x-1
x
x+1
-x
We have,
f(x)=sin2x and g(f(x))=|sinx|
Now,
g(f(x))=|sinx|⇒g(f(x))=sin2x⇒g(sin2x)=sin2x∴g(x)=x