First slide
Introduction to limits
Question

 If fx=sinxcosxtanxx3x2x2x1x then limx0f(x)x2=

Moderate
Solution

fx=sinxcosxtanxx1x2x2x1x

divide LHS by x2 and C1 and C3  by x in RHS

f(x)x2=sinxxcosxtanxxx2x21211

limx0f(x)x2=1    1    10    0    12    1    1=1

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