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Q.

If f(x)=sin⁡x+cos⁡x,g(x)=x2−1, then g(f(x)) is invertible in the domain

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a

0,π2

b

−π4,π4

c

−π2,π2

d

[0,π]

answer is B.

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Detailed Solution

fx= sinx+cosx , gx=x2-1   gfx=gsinx +cosx=sinx +cosx2-1 =1 +2sinx·cosx -1=sin2x  sin 2x is invertible if 2x∈-π2,π2 ⇒x∈-π4,π4
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