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Q.

If fx=sinx+cosx,gx=x2-1, then gfx is invertible in the domain

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a

0,π2

b

-π4,π4

c

-π2,π2

d

0,π

answer is B.

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Detailed Solution

fx=sinx+cosx,gx=x2-1⇒gfx=sinx+cosx2-1=sin2xClearly  gfx   is   invertible  in  -π2≤2x≤π2                        sinθ  is  invertible  when   -π/2≤θ≤π/2⇒     -π4≤x≤π4
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