First slide
Evaluation of definite integrals
Question

If f(x)=0sin2xsin1tdt  and g(x)=

0cos2xcos1tdt then the value of f(x)+g(x)

Moderate
Solution

f(x)+g(x)=sin1(sinx)2sinxcosxcos1(cosx)2sinxcosx

=xsin2xxsin2x=0

for all xR. Hence f(x)+g(x)= constant =C (say) 

Putting x=π/4,C=01/2sin1tdt+01/2cos1tdt

=01/2π2dt=π4

Hence f(x)+g(x)=π/4

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