If f(x)= sinx+sin2x+sin3xsin2xsin3x3+4sinx34sinx1+sinxsinx1 then the value of ∫0π/2 f(x)dx is
3
0
2/3
1/3
By applying the operation C1→C1−C2−C3,f(x) can be written as
f(x)=sinxsin2xsin3x034sinx0sinx1=sinx3−4sin2x=sin3x
So ∫0π/2 f(x)dx=−cos3x30π/2=13.