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If f(x)= sinx+sin2x+sin3xsin2xsin3x3+4sinx34sinx1+sinxsinx1 then the value of 0π/2f(x)dx is

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a
3
b
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c
2/3
d
1/3

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detailed solution

Correct option is D

By applying the operation C1→C1−C2−C3,f(x) can be written as f(x)=sin⁡xsin⁡2xsin⁡3x034sin⁡x0sin⁡x1=sin⁡x3−4sin2⁡x=sin⁡3xSo ∫0π/2 f(x)dx=−cos⁡3x30π/2=13.


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