If f(x)= sinx+sin2x+sin3xsin2xsin3x3+4sinx34sinx1+sinxsinx1 then the value of ∫0π/2 f(x)dx is
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a
3
b
0
c
2/3
d
1/3
answer is D.
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Detailed Solution
By applying the operation C1→C1−C2−C3,f(x) can be written as f(x)=sinxsin2xsin3x034sinx0sinx1=sinx3−4sin2x=sin3xSo ∫0π/2 f(x)dx=−cos3x30π/2=13.