If fx=sin(a+2)x+sinxx;x<0b;x=0x+3x21/3-x1/3x4/3;x>0  is continuous at x=0 , then a+2b is equal to:

We have left hand limit as a+3,f(0)=b and right-hand limit is limh→0(1+3h)13-1h=1For it to be continuous, left hand limit is equal to the right-hand limit and it is also equal to f0 So, we get a=-2,b=1 and a+2b=0