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Questions  

If f(x)=(1+tan x)(1+tan(π/4x)) and g(x) is a function with domain R, then

01x3gf(x)dx is

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a
12g(π/4)
b
14g(2)
c
14g(1)
d
none of these

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detailed solution

Correct option is B

f(x)=(1+tan⁡ x)1+1−tan⁡ x1+tan⁡ x=(1+tan⁡ x)21+tan⁡ x=2.So               ∫01 x3g∘f(x)dx=∫01 x3g(2)dx=x4g(2)401=14g(2).


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